(©2007, François G. Amar, All rights reserved)
(MWF 11AM)
For this week: Chapter 5.5-5.8
End of Chapter 5: 46, 47, 50, 53, 56, 58, 67, 71, 75
OWL Assignment for Week 8:
Chapter 5 assignment (called Ch 6 in OWL) thermodynamics: due October 28, 2007
Use tabulated values to predict the heat of reaction
Some examples (1 and 2 are formation reactions, 3 is a combustion reaction):
1) H2 (g) ---> H2 (g)H°f =
Hrxn = Hfinal - Hinitial = 0 2) H2 (g) + 1/2 O2 (g) ---> H2O (l) (1 mol)x(0 kJ/mol) + (1/2 mol)x(0 kJ/mol) ---> (1 mol)x(-285.83 kJ/mol) reactants (initial) ---> products (final)
H°rxn = Sproducts(molesx
H°f) - Sreactants(molesx
H°f)
H°rxn = -285.83 kJ for reaction (2) as written 3) C2H6 (g) + 7/2 O2 (g) ---> 2 CO2 (g) + 3 H2O (l) (1 mol)x(-84.68 kJ/mol) + (7/2 mol)x(0 kJ/mol) ---> (2 mol)x(-393.5 kJ/mol) + (3 mol)x(-285.83 kJ/mol) reactants (initial) ---> products (final)
H°rxn = Sproducts(molesx
H°f) - Sreactants(molesx
H°f)
H°rxn = -1559.81 kJ for reaction (3) as written
- at constant P (qP=
Hsystem)
we can often approximate the specific heat of dilute aqueous solutions by
the value for pure water
qsolution = Csolution x
T = csolution x mass x
T
but
Hrxn = qrxn = - qsolution
Example: if a reaction performed in a coffee cup calorimeter is exothermic then the
heat absorbed by the solution, qsolution is positive (temperature of solution rises)
But this is an exothermic reaction (
Hrxn<0) in which no work is done so qrxn = - qsolution.
qcalorimeter = Ccalorimeter x
T
but
Erxn = qrxn = - qcalorimeter= - Ccalorimeter x
T
Example: if a reaction performed in a bomb calorimeter is exothermic then the
heat absorbed by the calorimeter assembly, qcalorimeter is positive (temperature of calorimeter rises)
But this is an exothermic reaction (
Erxn<0) in which no work is done so qrxn = - qcalorimeter.